Fisika 125°C=....°R 100°C=....°F 80°C=....°K 273°K=....°C 81°F=....°Cbantu jawab ya:)​

alberthahaneulv – March 14, 2023

125°C=....°R 100°C=....°F 80°C=....°K 273°K=....°C 81°F=....°C

bantu jawab ya:)​

125°C = °R

= 4/5 × 125

= 4 × 25

= 100°R

100°C = °F

= 100 × 9/5 + 32

= 20 × 9 + 32

= 180 + 32

= 212°F

80°C = °K

= 80 + 273,15

= 353,15°K

273°K = °C

= 273 - 273,15

= -0,15°C

81°F = °C

= (81 - 32) × 5/9

= 49 × 5/9

= 5,4444 × 5

= 27,222°C

[answer.2.content]