please help me asap
Materi : Bentuk Akar dan Pangkat
( 8x . x-⁴ )/( 4x³ )
= ( 8/4 )( x¹-⁴-³ )
= 2/x⁶
[ ( 3x )² . ( 2x⁵ ) ]/[ ( 3x )⁴ ]
= [ 9x² . 2x⁵ ]/[ 81x⁴ ]
= ( 9 × 2 )/81 . ( x²+⁵-⁴ )
= 2/9x³
a³/² . a¹/²
= a³/²+¹/²
= a⁴/²
= a²
[ ( a^y )( a¹/² ) ]/[ ( a³/² ) ]
= a^y+¹/²-³/²
= a^y-²/²
= a^y-¹
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Jawab:
Jawaban ada dibawah
Penjelasan dengan langkah-langkah:
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